Ever wonder where those super-scripted letters go?
SLOWLYDESPARATLYSLOWLYTHEREMAINS
OFPASSAGEDEBRISTHATENCUMBEREDT
HELOWERPArTOFTHEDOORWAYWASREMOV
EDWITHTREMBLINGHANDSIMADEATINY
BREACNINTHEUPPERLEFTHANDCORNERAN
DTHENWIDENINGTHEHOLEALITTLEIIN
SERTEDTHECANDLEANDPEEREDINTHEHOT
AIRESCAPINGFROMTHECHAMBERCaUSED
THEFLAMETOFLICKERBUTPRESENTLYDETA
ILSOFTHEROOMWITHINEMERGEDFROM
THEMISTXCANYOUSEEANyTHINGQ?
Well that’s awesome, they spell “ray”.
I don’t know what use it is to know where they are but maybe it’ll be useful some day to someone.
You’re welcome.
They also spell YRA which is Gaelic for the IRA but we can assume here that Sanborn is referencing the Provos. Besides a few splinter groups, they’ve mostly abandoned the reunification by force but at the time Kryptos was installed, I doubt they could have predicted the official end of the campaign in 2005.
Here is my opinion of the YAR in K3. I actually have 2 theories. Here’s the first. If you use the Vigenere method with the same pass keys as K2 (Kryptos and Abscissa) but instead of decrypting it you actually encrypt it. You end up with CIA. Coincidence? Maybe. It could be a clue that tells us that we need ENCRYPT K4 not decrypt it in order to get a readable message.
That is definitely an interesting theory. Do you mind if I repost your comment on the main page?
fire away
I’ve taken this theory farther with some interesting results. I’ll email them to you when I have time to express it in an understandable format.
Is there an email I can use to send you one of my results?
People can always email me at kryptos AT fan DOT com.
Did you get something to work that gives you BERLIN?
Yup and a tad more. But unlikely the solution. Email coming soon.
OK, mailed. Let me know if you got it?
Got it and read it. New stuff and not crazy. I liked it.
If you put your K3 plaintext on top of the tableau side (row by row), RAY overlays COR. Overlay on the K3 ciphertext and you get NER. Corner? Kind of a stretch. Doing the same with the other two quadrants seems to be garbage. Interesting that each of the rows has 31 characters.
For whatever reason, I always find myself going back to the YAR when stuck on any other process. I recently discovered that there are exactly 101 “Y”s, “A”s and “R” on the alphabet side of the sculpture. 101 is fairly close to the number of K4 characters. If you remove the 1st vertical ABC alphabet from that total you end up 98. If you then look at the corresponding locations of the 98 Y,A and Rs on the cipher side of the sculpture you end up with 97 characters and a question mark. Problem is… some of the 97 characters are part of K4. It worth noting however that of those 97 characters from the cipher side of the sculpture all 6 characters of my Beaufort Cipher Theory OTP are included. NYPVTT > ICXUEI = BERLIN