So it’s possible to make a lot of connections that are meaningless. 

I noticed that the Morse Code has 81 letters and K1 has 63.  Why would this matter?  Well, I’ve been trying unsuccessfully for awhile to find some kind of amazing keyword message in the Morse Code text.  In the course of this I counted the letters in the keywords: Palimpsest has 10 and Abscissa has 8.  So while pursuing a message, I really only had to work with 63 letters.  So then I started wondering why K1 was so short and the Morse Code so apparently worthless (so far).

So I idly wondered what would happen if you tried to remove the letters of K1 from the Morse Code.

Digetalinterpretatittisyourpositionvirtuallyinvisibleshadowforceslucidmemorysosrq

Between subtle shading and the absence of light lies the nuance of iqlusion

=

Digalitrprtatittisyourpoitionvirtallyinvisileshadoforceslucidmemorysosrq

because while the Morse Code only has 1 “B”, the K1 text has 3.  We can’t start making things up just to get an idea to work.  If all of the K1 text had been subtractable from the Morse code then I would be pretty excited but it didn’t so we move on.  I only say this to encourage others who are trying to solve Kryptos to put logical boundaries around what they’re willing to do and try.  All too often I’ll go to someone’s site or they’ll email me and there are always several crucial points where their idea didn’t work but they wanted it to so badly that they make little departures in logic to sort of blur past the idea’s failure.

Don’t be afraid to fail at this stuff.  There’s a reason you can see every attempt I’ve ever made on Kryptos, so you can either do it better or avoid wasting your time on something that won’t work.  You always find what you’re looking for in the last place you look.  The reason is that you’ve found it.  If I don’t find my keys in the first couple places I look, I can’t exactly convince my car to start by making some 31 page treatise about how by quantum mechanics, my keys are simultaneously where I thought they should be and yet not.

Kryptosfan