There’s been a lot of talk-talk about the fourth part of Kryptos.  I personally have talked quite a bit as well about the Morse code.

When we consider K4, the letter frequencies are muted, there’s only 2 e’s for example and a bunch of k’s.  Can’t work a substitution either, the other values are too similar.

Then we look to the Morse code with it’s 81 letters of weird phrases and all those e’s.

So many e’s.

What’s the point of all those e’s anyways?  I assumed the answer was that they wanted to make them palindromes once they were in Morse code.  I don’t think so anymore.

What’s the point then?  They have to serve some purpose.  I have a weakness for teleology…

I decided to stop fighting to get them to work on their own and combined K4 with the Morse code text, including all those damn e’s. 

This effectively solves the frequency problems.  How are they merged?  How am I supposed to know?  How many letters does that give us?  Well, we’ve got 97 from K4 and 81 from the phrases and if there’s 22 extra e’s then we get an even 200.  I count 203 right now but I may have to confirm how many there actually are tomorrow.

Has this been thought of?  Did anything come of it?  What’s the final number of letters?  How does this help?  Is this even rational?  Questions that will be explored but for now the idea has been presented and hopefully I or some other solver can shed light on whether it is a useful attempt or not.

OBKRUOXOGH
ULBSOLIFBB
WFLRVQQPRN
GKSSOTWTQS
JQSSEKZZWA
TJKLUDIAWI
NFBNYPVTTM
ZFPKWGDKZX
TJCDIGKUHU
AUEKCAREEV
IRTUALLYEE
EEEEEINVIS
IBLEDIGETA
LEEEINTERP
RETATIUEES
HADOWEEFOR
CESEEEEELU
CIDEEEMEMO
RYETISYOUR
POSITIONSO
SRQ

Ach lad, but the wee idea sure don be nice tho’ eh?

Kryptos Fan

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